Mth302 assignments solution idea

download free

Mth302 assignments solution idea ,Mth302 assignments idea, Mth302 assignments solution, assignment Idea Mth302, assignment Idea solution

Assignment #  1

Solution 1:

Present Value (loan)                 P          =?

Interest rate/annum                   i           =7%

Interest rate/month                    i           =7/12%            =0.005833      

Amount                                    R          =8450 Rs

Number of years                       N         =17

Number of periods                   n          =17*12            = 204

Using Formula              P=R(1-(1+i)-n)/i

Putting Values                           P=8450(1-(1+0.005833)^-204)/0.005833

                                                P=8450(1-(1.005833)^-204)/0.005833

                                                P=8450(1-0.3053)/0.005833

                                                P=8450(0.6947/0.005833)

                                                P=8450*119.098

                                                P=1006380 Rs

Solution 2:

Basic Salary                 =30000 Rs

Allowances                   =18000 Rs

Taxable Income            =?

% allowances               = (18000/30000)*100

                                    =60%

Allowed non taxable allowance =50%

                                                            =0.5*30000

                                                            =15000 Rs

So taxable allowances                           =60%-50%

                                                            =18000-15000

                                                            =3000 Rs

Hence 3000 Rs of allowances are taxable

Total taxable income                             =30000-3000

                                                            =33000 Rs

Solution 3:

(a)

Absent students             =3

Total students                            =24

% of students absent                 =?

% of students absent     =3/24*100

                                    =12.5%

(b)

%age of students absent                        =12.5%

Total students                                        =24

How many students are absent               =?

How many students are absent               =12.5% of 24

                                                            =12.5/100*24

                                                            =3

(c)

12.5% of class                                      =3 students

Total students enrolled in the class         =?

                                                            12.5/100* Total students enrolled in the class=3

Total students enrolled in the class         =3*100/12.5

                                                            =24

Solution 4:

Principle                                   P          =?

Interest rate/annum                   r           =25%

Interest rate/month                    r           =25/12%          =0.02083        

Accumulated Amount               A         =100,000 Rs

Number of years                       N         =5

Number of periods                   n          =5*12  = 60

Compound interest                               =?

Using Formula

                                                     A=P(1+r)^n

                                         100000 =P(1+0.02083)^60

                                           100000 =P(1.02083)^60

                                                100000 =P(3.445)

                                                  P=100000/3.445

                                                    P=29027.6 Rs

Compound interest                    =100000-29027.6

Solution 5:

                                                     =70972.4 Rs

Total payment                           P          =150000 Rs

Withdrawal after each 3 month    R       =6000 Rs

Interest rate/annum                   i           =12%

Interest rate/quarterly                i           =12/4%            =0.03  

Number of withdrawal  n          =?

Using Formula 

                        P=R(1-(1+i)^-n)/i

Putting Values

                        150000=6000(1-(1+0.03)^-n/0.03

                        150000=6000(1-(1.03)^-n/0.03

                        150000*0.03/6000=1-(1.03)^-n

0.75=1-(1.03)^-n

(1.03)^-n=1-0.75

(1.03)^-n=0.25

Taking Log

Log(1.03)^-n=log0.25

-n log 1.03= -0.60205999

n(0.01283722)= 0.60205999

As

n = 0.60205999/0.01283722

n = 46.899

Number of withdrawal           n  = 47